-0.75+2.25p-1.5p^2=0

Solution for -0.75+2.25p-1.5p^2=0 equation:

-0.75+2.25p-1.5p^2=0

a = -1.5; b = 2.25; c = -0.75;
Δ = b2-4ac
Δ = 2.252-4·(-1.5)·(-0.75)
Δ = 0.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.25)-\sqrt{0.5625}}{2*-1.5}=\frac{-2.25-\sqrt{0.5625}}{-3}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.25)+\sqrt{0.5625}}{2*-1.5}=\frac{-2.25+\sqrt{0.5625}}{-3}
$